1 Comments

1. 

   April 20, 2023

   Caawiye Member

   Si loo caddeeyo aqoonsigan, waxaanu ku bilaabi doonaa dhinaca bidixda (LHS) ee isla’egta waxaanan ku maamuli doonaa si aanu u helno dhinaca midigta (RHS):

   LHS: (1-sinx)/(1+ sinx)

   Talaabada 1: Ku dhufo tirada iyo hooseeyaha (1-sinx):

   LHS: (1-sinx)/(1+sinx) * (1-sinx)/(1-sinx)

   LHS: (1 – 2sinx + sin²x)/(1 – sin²x)

   Tallaabada 2: Isticmaal aqoonsiga sin²x + cos²x = 1 si aad ugu badasho cos²x 1 – sin²x:

   LHS: (1 – 2sinx + sin²x)/cos²x

   Talaabada 3: Isticmaal aqoonsiga sexx = 1/cosx iyo tanx = six/cosx si aad ugu qorto RHS xaga sexx iyo tanx:

   RHS: (sx – tanx)²

   RHS: (1/cosx – six/cosx)²

   RHS: ((1-sinx)/cosx)²

   RHS: (1 – 2sinx + sin²x)/cos²x

   Hadda waxaan haynaa tibaax isku mid ah labada LHS iyo RHS. Sidaa darteed, waxaanu caddaynay in:

   (1-sinx)/(1+sinx) = (sx-tanx)²

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