1-sinx/1+sinx=(secx-tanx)²

1 Answers
caawiyepanel
April 20, 2023, 12:30 am
Si loo caddeeyo aqoonsigan, waxaanu ku bilaabi doonaa dhinaca bidixda (LHS) ee isla'egta waxaanan ku maamuli doonaa si aanu u helno dhinaca midigta (RHS): LHS: (1-sinx)/(1+ sinx) Talaabada 1: Ku dhufo tirada iyo hooseeyaha (1-sinx): LHS: (1-sinx)/(1+sinx) * (1-sinx)/(1-sinx) LHS: (1 - 2sinx + sin²x)/(1 - sin²x) Tallaabada 2: Isticmaal aqoonsiga sin²x + cos²x = 1 si aad ugu badasho cos²x 1 - sin²x: LHS: (1 - 2sinx + sin²x)/cos²x Talaabada 3: Isticmaal aqoonsiga sexx = 1/cosx iyo tanx = six/cosx si aad ugu qorto RHS xaga sexx iyo tanx: RHS: (sx - tanx)² RHS: (1/cosx - six/cosx)² RHS: ((1-sinx)/cosx)² RHS: (1 - 2sinx + sin²x)/cos²x Hadda waxaan haynaa tibaax isku mid ah labada LHS iyo RHS. Sidaa darteed, waxaanu caddaynay in: (1-sinx)/(1+sinx) = (sx-tanx)²

Leave Answer

You must be logged in to answer.