1 Answers
Solution
a. \(Cosx=√(1-sin^2 ) x←√(1-(4/9))=-√5/3
Cost=√(1-sin^2 ) t←√(1-(1/9))=√8/9
Cos (x+t)=Cosxcost+Sinxsint
Cos (x+t)=-√5/3×√8/9-2/3×(-1/3)=(-√40)/27+2/9=(-√(40 )+6)/27.
Cos (x-t)=-√5/3×√8/3+2/3×(-1/3)=(-√40)/9-2/9 \)=
b. \(Cosx=√(1-sin^2 ) x←√(1-(5/49))=√44/7
Cost=√(1-sin^2 ) t←√(1-(6/64))=√58/8
Cos (x+t)=Cosxcost+Sinxsint
Cos (x+t)=√44/7×√58/8-√5/7×(√6/8)=√2552/56+√30/56 \)=
Cos (x-t)=√44/7×√58/8+√5/7×(√6/8)=√2552/56-√30/56 \)=
c. \(Sinx=√(1-cos^2 ) x←√(1-(2/16))=-√14/4
cost=√(1-sin^2 ) x←√(1-(5/36))=√29/6
Cos (x+t)=Cosxcost-Sinxsint
Cos (x+t)=√2/4×√29/6 -(-√14/4 )×(√5/6)=√58/24+√70/24=(√(58 )+√70)/24.
Cos (x-t)=√2/4×√29/6+(-√14/4 )×(√5/6)=√58/24-√70/24 \)=
a. Cos (x-t)=-√5/3×√8/3+2/3×(-1/3)=(-√40)/9-2/9=(-√(40 )-6)/9.
b. Cos (x-t)=√44/7×√58/8+√5/7×(√6/8)=√2552/56-√30/56=(√(2552 )-√30)/56.
c. Cos (x-t)=√2/4×√29/6+(-√14/4)×(√5/6)=√58/24-√70/24=(√(58 )-√70)/24.
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