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Aynu ka soo qaadno in qiimaha hal maro uu yahay x kun, qiimaha hal boorasada yahay y kun.
Marka loo eego dhibaatadu, waxaynu ognahay in:
x + y = 9 ( isla’egta 1 ) 3x + 2y = 240 ( isla’egta 2 )
Waxaan u baahanahay inaan ku xalino x iyo y.
Si tan loo sameeyo, waxaan isticmaali karnaa habka beddelka. Waxaan u xallin karnaa isla’egta 1 ee x marka loo eego y:
x = 9 – y
Markaa waxaynu ku beddelan karnaa odhaahdan x ee isla’egta 2:
3 (9 – y) + 2y = 240
Fududeynta isla’egtan, waxaan helnaa:
27 – 3y + 2y = 240
-y = 213
U qeybinta labada dhinac -1, waxaan heleynaa:
y = -213
Xalkani macno ma samaynayo maadaama qiimuhu aanu noqon karin mid xun.
Si loo xalliyo tan, waxaan laba-baari karnaa bayaanka dhibaatada oo aan xaqiijin karnaa inay sax tahay. Dhanka kale, anagoo u malaynayna inuu khalad ku jiray odhaahda dhibta, waa in aan haysanaa 4 maro iyo 2 bac halkii aan ka haysan lahaa 3 maro iyo 2 bac, waxaan ku socon karnaa sidan soo socota.
x + y = 9 ( isla’egta 1 ) 4x + 2y = 240 ( isla’egta 2 )
Waxaan u xallin karnaa isla’egta 1 ee x marka loo eego y:
x = 9 – y
Markaa waxaynu ku beddelan karnaa odhaahdan x ee isla’egta 2:
4 (9 – y) + 2y = 240
Fududeynta isla’egtan, waxaan helnaa:
36 – 4y + 2y = 240
-2y = 204
U qeybinta labada dhinac -2, waxaan heleynaa:
y = -102
Tani sidoo kale waa jawaab aan macno lahayn maadaama qiimuhu aanu noqon karin diidmo. Sidaa darteed, waxaa dhici karta in uu khalad ku jiro hadalka dhibka ama waxa laga yaabaa in aanu wayno macluumaadka qaar.